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Focal chord of y 2 16x is a tangent

WebThe focal chord to y2 = 16x is tangent to (x – 6)2 + y2 = 2, then the possible values of the slope of this chord, are (2003S)a){–1, 1}b){–2, 2}c){–2, –1/2}d){2, –1/2}Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE ... WebSOLUTION. Here, the focal chord of y2 =16x is tangent to circle (x−6)2+y2 = 2. ⇒ Focus of parabola as (a,0) i.e. (4,0) Now, tangents are drawn from (4,0) to (x−6)2+y2 = 2. Since, P …

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WebThe equation of a common tangent to the curves, y 2=16x and xy=−4 is A x+y+4=0 B x−2y+16=0 C 2x−y+2=0 D x−y+4=0 Medium Solution Verified by Toppr Correct option is D) Step 1: Use slope form of tangent equation of parabola Equation of tangent to parabola y 2=4ax in terms of slope ’m’ is y=mx+ ma WebThe focal chord to y2 =64x is tangent to (x−4)2+(y−2)2 =4 then the possible values of the slope of this chord is Q. The focal chord to y2 =16x is tangent to (x−6)2+y2 =2, then the possible value of the slope of this chord are Q. The focal chord to y2 =16x is tangent to (x−6)2+y2 =2, then slope of focal chord is Q. therapist aid ocd treatment https://group4materials.com

The focal chord to y2=16x is tangent to x−62+y2=2 then - Self …

WebPARABOLA ASSIGNMENT - Read online for free. ... Share with Email, opens mail client WebDec 1, 2024 · Focal chord of the parabola is tangent to the circle (x−6)^2+y^2=2. 2and (6,0) are radius and centre of the circle As radius is perpendicular to the tangent, we have length of tangent from (4,0) to the circle is = 2 . From the diagram, we have tan teta= 2/ 2=1⇒θ=45 Therefore, slope of the chord is ±1= (−1,1). Advertisement Answer WebAny chord through focus is called a focal chord and any chord perpendicular to ... 9 3 x 2 y2 Ex.2 Find the equation of the straight lines joining the foci of the ellipse 1 to the 25 16 x 2 y2 foci of the ... parallel to the line y + 2x = 4. Ex.2 Equation of the tangent to an ellipse 9x2 + 16y2 = 144 passing from (2, 3). ... signs of strong credit

A focal chord to parabola y^2=16x is a tangent to circle …

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Focal chord of y 2 16x is a tangent

Focal chord to y2=16x is tangent to x−62+y2=2 then the

WebT is a point on the tangent to a parabola y 2 = 4ax at its point P. TL and TN are the perpendiculars on the focal radius SP and the directrix of the parabola respectively. Then. A. SL = 2 (TN) B. 3 (SL) = 2 (TN) C. ... Let PSQ be the focal chord of … WebThe focal chord of \( y^{2}=16 x \) is tangent to\( \mathrm{P} \) \( (x-6)^{2}+y^{2}=2 \). Then the possible values of theW slope of this chord are:(1) \( 1,...

Focal chord of y 2 16x is a tangent

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WebA: Here, Circle with center O is having tangents JK, KL and JL. so JA¯≅JB¯ ⇒JA=JB (tangent to circle… question_answer Q: Find the surface area of the cone in terms of it. WebFocal chord to y 2 = 16 x i s t a n g e n t t o (x − 6) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are Q. The focal chord to y 2 = 16 x is tangent to ( x − 6 ) 2 + y 2 = 2 , then the possible values of the slope of this chord are

WebApr 10, 2024 · Even by your method where it seems you are first finding equation of tangent to the circle and equating it to the focal chord, Given the equation of the circle, taking … WebStep-1 Length of tangent : Given: The focal chord to y 2 = 16 x is tangent to (x – 6) 2 + y 2 = 2. The standard equation of the parabola is: y 2 = 4 a x. Comparing the given …

WebA: y=-2sin3x+90∘y=-2cos3x ∵sin90+θ=cosθ Sketch two cycle of the given trigonometric… question_answer Q: Find the value of each variable using the given chord and secant lengths. WebFocal chord to y 2=16 x is tangent to x 62+ y 2=2 then the possible values of the slopes of this chords,areA. 1,1B. 2,2C. 2, 1/2D. 2, 1/2 Question Focal chord to y 2 = 16 x i s t a n g e n t t o ( x − 6 ) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are

WebDec 23, 2024 · The tangent to the Parabola that is parallel to y=4x+1 is: y = 4x+5/16 Which meets the Parabola at the coordinate: (5/64,5/8) We have a parabola given by: y^2=5x graph{y^2=5x [-5, 5, -5, 5]} The gradient of the tangent to a curve at any particular point is given by the derivative of the curve at that point. So if we differentiate the parabola …

WebJan 11, 2024 · The focal chord to y^2 = 16 x is tangent to (x - 6)^2 + y^2 = 2 , then the possible value of the slope of this chord, are. ← Prev Question Next Question →. 0 … signs of stroke in the eyeWebGet an expert solution to The focal chord of the parabola ( y − 2 ) 2 = 16 ( x − 1 ) is a tangent to the circle x 2 + y 2 − 14 x − 4 y + 51 = 0 , then slope of the focal chord can be therapist aid worksheets weekly mood logWebClick here👆to get an answer to your question ️ The focal chord to y ^ 2 = 16 x is tangent to ( x - 6 ) ^ 2 + y ^ 2 = 2 then the possible values of the slope of this chord are Solve Study Textbooks Guides therapist aid urge surfing scriptWebOct 14, 2024 · The focal chord to y^2 =16x is tangent to (x–6)^2 +y2 = 2, then the possible value of the slope of this chord, are asked Oct 22, 2024 in Parabola by deepikaben ( … signs of summer keystone heightsWebMay 20, 2024 · The equation of common tangent to the curves y^2 = 16x and xy = –4, is : ... If one end of a focal chord of the parabola, y^2 = 16x is at (1, 4), then the length of this focal chord is : asked May 18, 2024 in Mathematics by Jagan (21.2k points) jee mains 2024; 0 votes. 1 answer. signs of t2dmWebSolution : tangent to the parabola y 2 = 9x is. y = mx + 9 4 m. Since it passes through (4,10) ∴ 10 = 4m + 9 4 m 16 m 2 – 40m + 9 = 0. m = 1 4, 9 4. ∴ Equation of tangent’s are y = x 4 + 9 & y = 9 x 4 + 1. Hope you learnt equation of tangent to parabola in point form, slope form and parametric form, learn more concepts of parabola and ... signs of syphilis infectionWebJan 11, 2024 · The focal chord to `y^2=16x` is tangent to `(x-6)^2+ y^2 =2` then the possible values of the slope of this chord asked Nov 15, 2024 in Parabola by kundansingh ( 95.2k points) class-12 signs of svt in women