WebFind an answer to your question c) How many terms of the AP 7, 11, ... Advertisement Advertisement Sankalp050 Sankalp050 QUESTION: How many terms of an arithmetic sequence 7,11,15,… must be added to get sum 250? Solution: 7, 11, 15, 19, 23 . . . . . . In the above AP, first term ‘a’= 7. WebThe given A.P. is: -6, -5, ............. Here, a = -6, Let -25 be the sum of n terms ∴ or or or or or n (n - 25) = -100 or or Here, the common difference is positive. ∴ The A.P. starts from negative terms and its terms are increasing. ∴ All the terms after 13th term are positive.
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WebAP will be –15, –13, –11, –9, –7 So, resulting sum will be –55 because all terms are negative. When n = 11, AP will be –15, –13, –11, –9, –7, –5, –3, –1, 1, 3, 5 So resulting sum will be –55 because the sum of terms 6 th to 11 th is zero. Concept: Sum of First n Terms of an A.P. Is there an error in this question or solution? WebAP = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 Given, a = 1, d = 2-1 = 1 and a n = 15 Now, by the formula we know; S n = n/2 [2a + (n − 1) × d] S 15 = 15/2 [2.1+ (15-1).1] = 15/2 [2+14] = 15/2 [16] = 15 x 8 = 120 Hence, …
WebThe AP is -6, -11/2, -5, … It is an AP with the first term as -6 and the common ratio is 1/2. Sn = -25 = (n/2) [2a + (n-1)d] = (n/2) [-12 + (n-1)* (1/2)] = (n/2) [-12–1/2 + (n/2)] = (n/2) [-25/2 + (n/2)] -25*4 = n [-25+n] n^2–25n+100 = 0 (n-20) (n-5) = 0 n = 20 or 5. So either 5 terms or 20 terms of the AP will add up to -25. Answer. 2.1K views WebGiven,a=−6d=− 211−(−6)= 21Formula,S n= 2n[2a+(n−1)d]−25= 2n[2(−6)+(n−1) 21]−50=n[ 2−24+n−1]n 2−25n+100=0(n−20)(n−5)=0∴n=5,20Therefore the number of terms …
WebQuestion How many terms of the A.P. −6,− 211,−5,... are needed to give the sum −25? Easy Solution Verified by Toppr It is known that, S n= 20n [2a+(n−1)d], where n= number … Web14 apr. 2024 · The team fired Hextall, Burke and assistant general manager Chris Pryor on Friday after the Penguins failed to reach the playoffs for the first time in 17 years. The …
WebSum of n AP terms = S n = n 2 [ 2 a + ( n − 1) d] Where a is first term of AP and d is difference between two consecutive terms of AP. Calculation: Given series is 2, 4, 6, 8, 10,....... a = 2 and d = 2 Let sum of n terms of AP is 210. Therefore, 210 = n 2 [ 2 × 2 + ( n − 1) 2] ⇒ n 2 + n - 210 = 0 ⇒ n 2 + 15n - 14n - 210 = 0
WebSolution Calculate the number of terms of the given A.P. Given, 9, 17, 25,... are in A.P. First term ( a) = 9 Common difference ( d) = 17 - 9 = 8 Sum of n terms ( S n) = 636 We know that, Sum of n terms, S n = n 2 2 a + ( n - 1) d Substituting the values in S n, we get chinese green tea imagesWeb19 mrt. 2024 · Find an answer to your question how many terms of the A.P -6,-11/2,-5 _____ are needed to give the sum - 25? Explain the double answer chandnidewangan787 chandnidewangan787 chinese green tea ballsWeb30 mrt. 2024 · AP is of the form 6, 11/2, 5 . Here First term = a = 6 Common difference = d = 11/2 ( 6) = 11/2 + 6 = ( 11 + 12 )/2 = 1/2 & Sum of n terms = Sn = 25 We need to find n We know that Sn = n/2 [2a + (n 1)d] Here, Sn = 25 , a = 6 , d =1/2 Putting values 25 = … grandmother mass shootingWeb9 dec. 2024 · Answer: No of terms = 5 ,20 Step-by-step explanation: Given : AP : -6, -11/2 , -5 To find: No of terms to give sum = -25 Steps: Firstly e calculate the common … grandmother mauled by family dogWebHow many terms of the A.P. −6,−11 2,−5,…… are needed to give the sum -25 ? Solution Let the number of terms to be added to the series is n Now a = -6 and d = 0.5 Therefore … grandmother mary\u0027s cookiesWebGiven AP is : 1, 6, 11, 16…… First term, a = 1 ; Common difference = 5 Sum of n terms of AP, Sn = (n/2) [2a+ (n-1)d] Let there be n terms in the AP such that Sn= 148 148= (n/2) [2 (1)+ (n-1) (5)] 148 = (n/2) [2+5n-5] 148 = (n/2) [5n-3] 5n²-3n-296=0 This equation has one +ve root, n= 8 8 terms of AP are , 1, 6, 11, 16, 21, 26, 31, 36 Ans: 8 terms 1 grandmother maryWeb19 dec. 2024 · ⇒ a + d = 2 and a + 6d = 22 Solving these two equations, we get a = – 2 and d = 4. S n = [2a + (n – 1) d] ∴ S 30 = [2 × (–2) + (30 – 1) × 4] ⇒ 15 (–4 + 116) = 15 × 112 = 1680 Hence, the sum of first 30 terms is 1680. Example 6: Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by 3. Solution. grandmother mauled to death by family dog